sorry, differentiate Y = ln(3x^4+2x) i dont get this much?

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i forgot to add that on the last one, sorry

2007-09-22 15:09:58 · 3 answers · asked by jake p 2 in Science & Mathematics ➔ Mathematics

remember , if y = ln(f(x))
dy/dx = f'(x)/f(x) ln e
y = ln(3x^4+2x)

dy/dx = (12x^3+2)/(3x^4+2x) ln e
since ln e = 1,
dy/dx = (12x^3+2)/(3x^4+2x)

2007-09-22 15:15:47 · answer #1 · answered by Anonymous · 0⤊ 0⤋

Hello,

(12x^3+2)/(3x^4+2x) dx

Hope This Helps!!

2007-09-22 22:19:49 · answer #2 · answered by CipherMan 5 · 0⤊ 0⤋

y ' = (12 x^3 + 2) / (3 x^4 + 2x)

2007-09-22 22:15:16 · answer #3 · answered by CPUcate 6 · 0⤊ 0⤋