how do u do this?

Question

Bornite (Cu3FeS3) is a copper ore used in the production of copper. When heated, the following reaction occurs.

2 Cu3FeS3(s) + 7 O2(g) 6 Cu(s) + 2 FeO(s) + 6 SO2(g)
If 4.48 metric tons of bornite is reacted with excess O2 and the process has an 83.7% yield of copper, what mass of copper is produced?

Answer 1

Atomic weights: Cu=63.5 Fe=55.8 S=32 Cu3FeS3=342.3

Let bornite be called B. Let a ton-mole be called tmol. Let a metric ton be called mt

4.48mtB x 1tmolB/342.3mtB x 6tmolCu/2tmolB x 63.5mtCu/1tmolCu x 83.7% = 2.09 metric tons Cu

Answer 2

Do the stoichiometry.

Calculate the molecular mass of the Bornite. Divide 4.48 metric tons (a metric ton is 1,000 Kg or 1 x10E6 grams) by the mol mass to get moles

Multiply by ht emolar ratio of 6 / 2 to get moles of copper. Now multiply by mol mass of copper to get the theoretical grams and convert to tons.

Multiply by 83.7% to get the actual amount recovered