lim
x->2.5
25 - 4x^2 / 2x + 5
2007-09-22 13:45:33 · 4 answers · asked by jake p 2 in Science & Mathematics ➔ Mathematics
If you plug in 2.5 into the numerator and denominator, you will get 0/10, which is 0. The question is asking what will happen to the function when x approaches 2.5. The numerator dominates and the whole function approaches 0.
2007-09-22 13:53:40 · answer #1 · answered by james w 5 · 0⤊ 0⤋
You gotta factor the top so that you get (5-2x)(5+2x)/(2x+5)
Now, you can cross out the common terms on the top and bottom, leaving you with (5-2x). Plugging in 2.5 gives you 0
2007-09-22 20:50:44 · answer #2 · answered by MateoFalcone 4 · 0⤊ 0⤋
just plug in 2.5, because it wont cause the denominator to be zero unless that was 2x-5
2007-09-22 20:50:38 · answer #3 · answered by intrepid_mesmer 3 · 0⤊ 0⤋
=(5-2x)*(5+2x)/(2x+5) = 5-2x= 0
I think it should be 2x-5 in the denominator so you get
=-(5+2x)=-10
2007-09-22 20:54:47 · answer #4 · answered by santmann2002 7 · 0⤊ 0⤋