need further help, please?

Question

Physics question, I can't seem to get this problem, please help.?
Two forces, 381N at 8deg. & 307N at 25deg. are applied to a car in an effort to accelerate it.?
What is the magnitude of the resultant of
these two forces?

What is the direction of the resultant force (in re-
lation to forward, with counterclockwise con-
sidered positive)?????
within the
limits of -180deg to 180deg

Additional Details


655.52 was the answer for the first question... and so if 655.52 is the resultant force, what is the direction of deg?

Answer 1

Resolve the two forces in rectangular coordinates, using sines and cosines. Then add the x components of the two forces together and do the same for the y components. The result is the x and y components of the "net" force. Then using Pythagorean theorem, solving for the hypotanuse, you get the magnatude of the resultant force. Use inverse tangent to get the angle.

Answer 2

If this is for webassign, I feel your pain comrade.
Okay, here was my original question:
Two forces are applied to a car in an effort to move it.
First force: 10 degrees west of north @ 450 Newtons
2nd force: 30 degrees east of north @400 Newtons
I'll answer your question with this example (the questions sound similar, if not the same altogether).

Split the vectors into their own x and y components. It sounds like you know how to find them with trig.
Then, add the y components of both vectors.
DO NOT ADD THE X COMPONENTS.
Subract the x components: the forces are in different directions in regard to the x component, but they are both going forward in the y direction.

Use trig to find the hypotenuse (magnitude of vector) and inverse tangent to find the angle (tan=opp/adjacent. angle=inverse tan x opp/adj) The angle that you are trying to find is clockwise from north.

I guess you just needed that last part for your answer, but mine came out correct so... hope I could help!!

Answer 3

west