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Its CuSO4 + Na2CO3 produces CuCO3 + Na2SO4 and I need to find the percent yield, and CuCO3 is the precipitate. My theoretical yield is 0.615 g but for the actual yield I got 0.116 g so I was wondering what other people may have gotten for their actual mass.

2007-09-22 12:41:38 · 1 answers · asked by <3DA<3 1 in Science & Mathematics Chemistry

1 answers

What's wrong with obtaining less than you thought you should get? It only shows that CuCO3 is not totally insoluble, or you didn't filter properly (or whatever method you used).

2007-09-22 21:03:31 · answer #1 · answered by Gervald F 7 · 0 0

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