15x= 350 + x^2
2007-09-22 12:28:44 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x^2 - 15x + 350 = 0
After that use Quadratic Formula!
a=1
b=-15
c=350
x = [15 +/- Sq.Root(-15^2 - 4(1)(350)]/2(1)
x= 7.5 plus 17.139 i
x = 7.5 minus 17.139 i
2007-09-22 12:36:30 · answer #1 · answered by sumisashimi 1 · 0⤊ 0⤋
Bring the 15x over to the other side as a negative.
So, it looks like this:
x^2 -15x + 350=0
The quadratic equation states that:
ax^2 + bx + c = 0
So, substitute 1 for a, since x^2 is the same thing as 1x^2. Then negative 15 for b, then 350 for c.
The quadratic formula is:
Sorry, I can't type it all here, but go to Wikipedia, type in quadratic formula, and scroll down, you'll see it!
Good luck!
2007-09-22 12:51:46 · answer #2 · answered by funkyducky7890 1 · 0⤊ 0⤋
0=350-15x+x^2
quadratic formula:
x=(-b±√(b^2-4ac))/2a
x= (15±√(225-4(1)(350))/(2(1))
x= (15±√(-1175))/2
x= (15±5i√(47))/(2)
x= 15/2 +5√(47)i, 15/2 -5√(47)i
2007-09-22 12:45:51 · answer #3 · answered by Dwasa 2 · 0⤊ 0⤋
x^2 - 15x + 350 = 0
350 is too big
the root is imaginary
2007-09-22 12:39:44 · answer #4 · answered by CPUcate 6 · 0⤊ 0⤋
x ² - 15x + 350 = 0
x = [ 15 ± √(225 - 1400) ] / 2
x = [15 ± √( - 1175 ) ] / 2
x = [ 15 ± i √(1175) ] / 2
2007-09-24 07:18:24 · answer #5 · answered by Como 7 · 0⤊ 0⤋
all i know is this can be solved using quadratic equations...gosh, i need to catch up on my math!!
2007-09-22 12:40:53 · answer #6 · answered by ? 3 · 0⤊ 0⤋
I thought you figured it out already...
GOSH!
2007-09-22 16:45:46 · answer #7 · answered by Sea Legs 4 · 0⤊ 0⤋