What is the derivative of f(x)= 1/(x-7) ?

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2007-09-22 11:08:11 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

f(x)=(x-7)^-1, therefore the derivitive of it is f(x')=1/(x-7)², or (x-7)^-2

2007-09-22 11:31:28 · answer #1 · answered by Anonymous · 0⤊ 0⤋

f(x) = (x-7)^(-1)
f '(x) = - (x-7)^(-2)
f '(x) = -1 / (x-7)^2
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2007-09-22 18:16:05 · answer #2 · answered by CPUcate 6 · 0⤊ 0⤋

u = x-7
du = dx

df(x) = -1/u^2 du = -1/(x-7)^2

2007-09-22 18:15:46 · answer #3 · answered by lhvinny 7 · 0⤊ 0⤋

Substitute y = (x-7) then df/dx = df/dy(dy/dx)
dy/dx =1 So df/dx =df/dy = -1/y^2 =[-1/(x-7)^2]

2007-09-22 18:24:21 · answer #4 · answered by stvenryn 4 · 0⤊ 0⤋