Elemental ananalysis of a compound results in the following data
41.39 % C
3.47 % H
55.14 % O
What is the empircal formula of this compound ?
2007-09-22 08:40:56 · 4 answers · asked by mike m 1 in Science & Mathematics ➔ Chemistry
Say you have 100g of this compound. U'd have 41.39 g C, 2.47g H and 55.14g O. Divide each with its atomic mass. For example: 55.14g O / 16.00 g O. That should naturally give you three results. Divide the two biggest results by the smallest and you'll have a number for each element.
2007-09-22 08:57:54 · answer #1 · answered by Alejandro Sutter 1 · 0⤊ 0⤋
Divide each percentage by the Ar of that element, and then by 3.4, and you will see that the ratio is 1:1:1 ie CHO.
2007-09-22 08:51:32 · answer #2 · answered by Gervald F 7 · 0⤊ 0⤋
What molecular ...? if u mean the molecular weight of the compound then it is 52 . 0.25 moles of the compound ---------------------> 13g 1mole of the compound -----------------------------> ? (x) 1 mole = 52 grams. n = molecular formula/ empirical formula mass n = 52/13 n= 4 therefore the compound is C4H4.all its bonds are double.
2016-05-21 00:46:13 · answer #3 · answered by shawna 3 · 0⤊ 0⤋
C12H1O16
2007-09-22 08:51:08 · answer #4 · answered by jared999 1 · 0⤊ 1⤋