Can anyone explain whether this is a possible scenario or not and why?
thanks!
2007-09-22 08:20:51 · 5 answers · asked by sungirl 2 in Science & Mathematics ➔ Physics
Absolutely.
Throw a ball straight up in the air.
Consider that ball at the apex of its path.
v = 0, a = -g
2007-09-22 08:26:07 · answer #1 · answered by Anonymous · 1⤊ 0⤋
Yep. It's possible.... if you look at it this way it can happen. Remember that acceleration is the differential of speed. Right?
Imagine you have speed described by
v(t) = Asin(t)
So the acceleration would be
a(t)= Acos(t).
Being A any constant. If you take the instantant t = 0, you would know that
V(0)= 0
and
a(t) = A
because cos of 0 is one...
So it could happen. Imagine... a car that is stoping... it is de-accelerating, and when itg get's to zero, even then it would have been de-accelerating.
2007-09-22 15:32:09 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Non - zero acceleration?
I know that in SHM, when velocity is at a maximum, acceleration is zero
The only thing I can think of is a Parabola
I mean the top of a Parabola. v = 0
2007-09-22 15:25:22 · answer #3 · answered by 4 · 0⤊ 0⤋
Yes, Velocity is speed in any given direction(north, south, west, etc) If a car is turning in circles it has no direction. Therefore it has no velocity. It can though, accelerate. So a possible scenario would be a car turning in circles and accelerating as it turns.
2007-09-22 15:31:04 · answer #4 · answered by Ariel A 2 · 0⤊ 1⤋
Sure it is. A ball thrown upwards has the acceleration of gravity on it at all times, but at the top of its path its velocity is zero.
Doug
2007-09-22 15:27:37 · answer #5 · answered by doug_donaghue 7 · 1⤊ 0⤋