Ignore air friction. An object dropped at Earth surface has a constant acceleration of 9.8m/s^2. This means...

Question

A. the speed of the object as it falls is 9.8m/s.
B. the object falls 9.8 meters during the first second only.
C. derivative of the distance with respect to time for the object equals 9.8m/s^2.
D. speed of object increases 9.8 m/s during each second
E. object falls 9.8 meters during each second

I think its D

Answer 1

I think you're correct ☺
It's velocity increases by another 9.8 m/s for every second that it falls. That's 9.8 meters per second, per second. or 9.8 m/s²

Doug

Answer 2

nicely there's a difficult worded question. it may would desire to be consistent. I got here to my end this way. If it grew to become into increasing then it could have some form of propulsion subsequently it might desire to now not be viewed falling. It for sure would not cut back, gravity would not enable for that. And all of us found out on Mr. wizard that weight maters now not. (remember whilst he dropped the wadded up piece of paper next to the lots heavier baseball. They the two hit the floor on the comparable time. Plus in case you have now not ever heard this that's gonna blow your concepts. in case you dropped a bullet on the comparable appropriate time one left the barrel of a gun because it grew to become into fired they could the two hit the floor on the comparable time. It has to do with gravity impacts each and every thing the two if there isn't any air in touch. Neat huh?

Answer 3

You are correct.

The speed increases because the object is dropping. If the object were flying up, though, the speed would be decreasing of course.