2007-09-22 01:17:21 · 11 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
When you multiply two variables with the same base, you add the exponents.
"Keep the base, add the exponents."
Therefore, 3+-3=0, so, you would be left with m^0, and anything to the zero power is 1.
2007-09-22 01:26:04 · answer #1 · answered by loser 4 · 0⤊ 0⤋
m^-3=1/m^3.
2007-09-22 02:43:14 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Multiplying
m ³ x m (- ³) = m^0 = 1
Dividing
m³ / m^(-3) = m³ x m³ = m^6
2007-09-22 20:35:13 · answer #3 · answered by Como 7 · 0⤊ 0⤋
yes they do cancel each other,
m^-3 is 1/m^3
nd when it is multiplied with m^3,
m^3 * 1/m^3
where both cacel each other nd ans is 1
2007-09-22 01:26:59 · answer #4 · answered by define.. 2 · 0⤊ 0⤋
Only if you are multiplying them together.
m^3 * m^-3 = m^0 = 1
m^3/m^-3 = m^6
adding is a totally different story.
2007-09-22 01:27:30 · answer #5 · answered by ccw 4 · 1⤊ 0⤋
If you're multiplying them yes.
m^(3-3)=m^0=1
2007-09-22 01:33:35 · answer #6 · answered by noodlemaster 1 · 0⤊ 0⤋
If you are multiplying them, yes.
m^3 x m^-3 = m^0 =1
If you are dividing them, no
m^3 / m^-3 = m^6
If you are adding them, no
m^3 + m^-3 = m^3 +1/m^3 = (m^6+1)/m^3
2007-09-22 01:26:28 · answer #7 · answered by Anonymous · 3⤊ 0⤋
depends on the operation.
m^3 + m^-3 is m^3 + m^-3.
m^3 - m^-3 is m^3 - m^-3
m^3 * m^-3 = 1
m^3 / m^-3 = m^6
2007-09-22 01:31:56 · answer #8 · answered by reg 5 · 1⤊ 0⤋
yes it cancels out when you multiply them
2007-09-22 01:32:39 · answer #9 · answered by sudarshan k 1 · 0⤊ 0⤋
yes.
2007-09-22 01:23:36 · answer #10 · answered by 2hard4me 3 · 0⤊ 0⤋