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the height of an object thrown in the air is:

h= -9.8t + 129.8(1- e^(-t))

find:
1) max height in meters (2 decimal pts)
2) time taken to return to the ground in seconds (2 deci pts)

2007-09-22 00:59:46 · 1 answers · asked by Anonymous in Science & Mathematics Physics

1 answers

I seriously doubt that this is th eequation for an object thrown in the air.


Let's do some Calc.

Min/Max is at h'(t)=0

To test for max set h''(t)=0

h'=-9.8 + 129.8 (0 + e^(-t) )
at h'=0 t=ln(9.8/129.8)

I guess we have no way to test ...LOL

2007-09-22 07:54:21 · answer #1 · answered by Edward 7 · 0 0

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