I need the formula?

Question

or computation, not sure of the word, for lottery works syndicate. There are 10 of us with 1 line each = 10 lines, how can we cover our lines with min/max numbers? ie. we have 3 numbers up on one line, how do I work out that we are guaranteed 3min on other lines etc. Can someone give me the formula as to cover all these lines. realise I may not have worded this properly, but relying on maths/numbers people will understand what I mean, basically want to cover all lines in the event of 3 or more numbers coming up. many thanks in advance.

Edit.
I think its a permutation: with set amount of numbers.

And maybe using min 2/3 numbers throughout as bankers, does that help?

More explicit now: what is the minimum numbers I can use throughout my 10 line numbers, so that they are covered in all other lines, Total numbers = 10 x 6 = 60. for example can i use maybe 20 same numbers throughout my 10 lines and be covered, does that help , sorry for the confusion, so unsure how to describe this.

Al: I think your near the mark, 'cos about a year ago I picked 2numbers throughout my 10 lines as bankers, those 2 numbers came up. I got four winning lines, OK 3 were for £10 but the 4th got me something like £90 for 4numbers.

Will come back later on this, 'cos haven't expressed myself well. Max 10x6 lines =60. what is minimum numbers I can use repetitive throughout to cover my lines... if certain numbers come up??
Thanks all for your help.

Answer 1

Try to re-phrase and ask again, I'm confused about what you're asking!

I think I know what you mean, by having say 3 numbers the same on all the lines then 3 differing numbers?

If so, then it would only work if those numbers came up, and the chances of that is less likely to result in a win than if you were to pick 6 random numbers on all the lines. Although the win would be bigger, the unlikelyhood of them coming up outweighs this.

Answer 2

OK I think we've cracked it!
Let's say the 'winning' 3 Number line is
a,b,c,d,e,f . (like 3,6,11,23,29,45)
There are exactly 20 possible permutations (where order does not matter) of any 3 selections from 6 (6!/(6-3)!*(3!)
where 6!=6x5x4x3x2x1 etc
So if any one line contains 3 correct numbers (which 3 you do not know in advance), the other lines must contain each the other possible permutations.
The 'chosen' line is a,b,c,d,e,f
The other lines must contain resp
(a,b,c).. a,b,d..a,b,e..a,b,e
a,c,d..a,c,e..a,c,f
a,d,e...a,d,f
a,e,f.
b,c,d...b,c,e..b,c,f
b,d,e..b,d,f
b,e,f
c,d,e..c,d,f
c,e,f
and finally d,e,f! (in addition to any other 3 random numbers)
So chose a line a,b,c,d,e,f (any numbers between 1 and 49) and make sure (you need another 19 lines) that each of them contains (a different) one of the number letter triplets.
I think that this guarantees that if one line is correct at least one of the other nineteen will contain a winning three-up too. This is still not beating the odds!
Your probability of winning £20 is still only 20/55=36% for a £20 stake since the prob of one line yielding 3 is still 1/55.

Answer 3

do you mean the lottery?
the formula is
49 x 48 x47
_________________
1x 2 x3
this is the number of lines you need to put on if you only pick 3 numbers.
49x48x47x46
___________
1x2x3x4
is for 4 numbers
etc
hope this helps ,its a lot of money to pay out to win a tenner .lol
in all cases divide the top line by the bottom line.

Answer 4

You would need a lot more than 10 lines, ther are 14 million permitations for sixnumbersAnd many more for three. good luck and send me a share when you win.

Answer 5

Dodger, you must stop dodging the question and provide a better description. Otherwise you will not get any answers that are useful to you.

Answer 6

stone the flamin crows mate its too late for sums

Answer 7

oh oh pass

Answer 8

Do any of these this help? :-)