heh, this is for some take home quiz and the question is worded exactly like this
not sure if the lamps were turned on in the first place but that is probably assumed
answer choices include:
a- Both maps would be off
b- L1 would be on and L2 would be off
c- L1 would be off and L2 would be on
d- Both lamps would be on
i think the answer would be d because of the solder bridge but not sure...
and also, what if L1 was opened instead of shorted?
what do you guys think? (thanks for the help guys)
2007-09-19 11:29:27 · 5 answers · asked by HChen87 1 in Science & Mathematics ➔ Engineering
er... not maps, lamps
2007-09-19 11:31:26 · update #1
Both lamps would be off. Since the lamps are in parallel they share the connections, so shorting L1 also shorts L2. Then there is no way for either one to get electricity and that means both are off.
2007-09-19 11:56:16 · answer #1 · answered by Rich Z 7 · 1⤊ 0⤋
Both of the lamps would go off. This is ue to the solder bridge. If the solder bridge shorts L1 then it will also short L2 because they're both connected in parallel. The parallel connection makes both lamps to have the same voltage across their terminals. The short circuit caused by the solder bridge makes this voltage to drop to zero. Since the lamps were in parallel they both experience the same voltage after the short circuit (zero). Therefore no current can pass through any of the lamps regardless their previous condition (off, on, open-circuited, etc.). So the correct answer is letter "a".
2007-09-19 12:51:36 · answer #2 · answered by carlos h 1 · 1⤊ 0⤋
Write the two equations in general form: L1: y = (a million/5)x - 4 L2: y = -5x + 5 because of the fact that L1's slope is a million/5 and L2's is -5, and (a million/5)*(-5) = -a million, those 2 strains are perpendicular to a minimal of one yet another. Regards Tonio
2017-01-02 10:03:44 · answer #3 · answered by ? 3 · 0⤊ 0⤋
Both would go off, (a is correct) the current passes through the path of least resistance, in this case the short.
If L1 was open instead L1 would go off and L2 would stay on. No current would pass thru L1 because of the open, but L2 would stay on, unless the open is also in the current path of L2.
2007-09-19 11:38:45 · answer #4 · answered by Barcadcadacada 6 · 1⤊ 0⤋
In series means that if one light goes out the rest of the series does after it. Parallel means that if one light goes out the rest will stay illuminated. The answer is c:
If L1 was open? could mean shorted or it could mean the bulb has been removed, etc. the same would apply.
2007-09-19 11:42:26 · answer #5 · answered by neonman 7 · 0⤊ 3⤋