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All 1 ohm resistors.

2007-09-19 03:09:24 · 4 answers · asked by Anonymous in Science & Mathematics Engineering

http://s223.photobucket.com/albums/dd78/floodtl/?action=view¤t=Resistors.jpg

Explain how you got the second one.

2007-09-19 03:10:08 · update #1

4 answers

Hey there... Kirchhoff's law strikes again!!!!...I took a look at the pic and thought ....we know how to do this but lets ponder the applications theory first..Once we have found the ckt paths and located the parallel ones and the series ones and the series/parallel ones...its mostly just plane ole arithmetic...Pheeeew!
Well in the second example you have modified the location of A and since the reference EMF is A->B the rest of the ckt is dead (relative to A or B) ...so the total r for that is 1/r(T)=1/r1+1/r2 now don't forget to add the two one ohm together to make each branch 2 Ohms ,,,moving B to any other location will either be that total r or 1ohm....Whatcha think?,,well there ya go...From the E...

2007-09-19 05:14:34 · answer #1 · answered by Edesigner 6 · 1 0

0.6 ohms, and 1 ohm. A to B in matrix #2 the current would divide into 2 parallel paths. That makes 2 sets of 1 ohm resistors in parallel. Using the formula R1+R2/R1xR2, gives 2+2=4/2x2=4=1.

2007-09-19 12:14:57 · answer #2 · answered by Anonymous · 0 1

☺your choice of snotty whiz-kid A-der was correct the day before!
R={1/(1/3 +1) +1}/2 = 7/8 Ohm;
2 leftmost resisters are not to be taken into account;
http://i174.photobucket.com/albums/w119/kaksi_guy/2.png

2007-09-19 14:55:05 · answer #3 · answered by Anonymous · 0 0

Doin' that many mesh equations at this hour of the morning is -not- gonna happen ☺
Maybe I'll fire up Electronics Workbench later on and see what it says.

Doug

2007-09-19 10:25:03 · answer #4 · answered by doug_donaghue 7 · 1 0

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