2007-09-18 16:28:36 · 5 answers · asked by cb_schulman 1 in Science & Mathematics ➔ Engineering
Define straight. Are they both horizontal/vertical? Then, no, they never cross.
Bottom line: if they both have the same slope or slant, then they do not touch, unless they are the same line.
2007-09-18 16:34:29 · answer #1 · answered by Matiego 3 · 0⤊ 0⤋
In planer Geometry the z dimension is not recognized so at best one might say that if the line are alike in all respects one is equal to the other but does not cross it. I n 3d imaging two straight lines from any view except standard (top,left ,right ,bottom) can appear to cross But in Boolean terms crossing is the intersection of two points not the paralleling...See ya later ...Boolean 3d modeling is one of my best subjects if you ever need help with that..FYI....From the E...
2007-09-18 16:50:26 · answer #2 · answered by Edesigner 6 · 0⤊ 0⤋
Two superimposed lines, mathematically, become one line. A line does not intersect itself. But in CAD/CAM software they are recognized as two separate lines. If they are the same length then Mastercam calls them duplicate entities and may automatically delete one of them. Duplicate entities will cause problems for a machinist trying to manufacture a part from your CAD file.
2007-09-18 16:44:40 · answer #3 · answered by Anonymous · 0⤊ 0⤋
a) At component C, it crosses the x axis, consequently y=0. replace that into the equation x+y=8, and we see that x=8 so the co-ordinates for C are (8,0). At component D, it crosses the y axis, consequently x=0. replace this too, and we are able to locate that y=8 so the co-ordinates for D are (0,8) b) First we might desire to locate the equation of l1. we are able to first locate the gradient by ability of utilizing the formulation: m=(y-y1)/(x-x1). So positioned the values into this formulation and it will become: m=(7--2)/(6-0) = 9/6 = 3/2, so the equation will initiate with y=3/2x. Now to locate the consistent, we might desire to alter values into the formulation: y=mx+c, because of the fact all of us be conscious of x and y (from between the coordinates) and we now be conscious of m. This turns the formulation into 7=3/2(6)+c. So 7=9+c. So c=-2. positioned them at the same time and the equation of l1 is y=3/2x-2. Now to be sure the coordinates of E, we've 2 equations of the two strains to artwork with: x+y=8 and y=3/2x-2. Rearrange the 1st equation to place it equivalent to y, which turns it into y=8-x. Now the two equations are equivalent to y, consequently we are able to assert that they are equivalent to a minimal of one yet another. so we are able to make the equation: 8-x=3/2x-2. upload x to the two factors: 8=5/2x-2. upload 2 to the two factors: 10=5/2x. So x=4. We then replace this cost for x into between the equations. permit's positioned it into y=8-x, so y=8-4, so y=4. consequently the coordinates of E are (4,4) c) The formulation to locate the section of a triangle from the coordinates is (brace your self): Ax(by ability of-Cy)+Bx(Cy-Ay)+Cx(Ay-by ability of) All divided by ability of two the place Ax and Ay are the x and y coordinates of the component A and so on. because of the fact we might desire to apply D and E, permit's say B=D and C=E Coordinates of A: (0,-2) Coordinates of D or B: (0,8) Coordinates of E or C: (4,4) replace the coordinates into the equation: 0(8-4)+0(4--2)+4(-2-8) All divided by ability of two = -40/2 = -20. areas won't be in a position to have a unfavorable cost, so the section = 20
2017-01-02 09:08:51 · answer #4 · answered by Anonymous · 0⤊ 0⤋
No. If they contain exactly the same points, then they are the same line. Lines only intersect when they have -one- point in common.
Doug
2007-09-18 16:46:02 · answer #5 · answered by doug_donaghue 7 · 0⤊ 0⤋