A 4.0 hp lawnmower engine moves the mower with a force of 1,492 N over a distance of 100.0 m.How much time did

0 ⤊

this require?

2007-09-17 12:42:05 · 2 answers · asked by sojo3 1 in Science & Mathematics ➔ Engineering

Work (energy) = Force * distance

Power = Energy / time

149,200 Joules / (4 HP * 746 Joules/sec/HP) = 50 sec.

.

2007-09-17 13:00:25 · answer #1 · answered by tlbs101 7 · 0⤊ 0⤋

set up a porportion.
4.0*100/1492
(4 times 100 divided by 1492)

2007-09-17 19:48:01 · answer #2 · answered by bleach145 1 · 0⤊ 0⤋