Okay, here is the word problem, with the answers we were supposed to get... HOW are we to end up with these? All 10 of us in the class do NOT get these answers...
On Oct 1, 2003, the Topeka Capital Journal ran a featured article on making cake frosting. The recipe called for an 8-ounce package of cream cheese, 1/2 cup of butter, 2 teaspoons of vanilla, and 3/4 cup of confectioner's sugar. If Mr. Baker watns to reduce the recipe by 1/3, how much of each ingredient would he need?
These are the answers in the back of the book:
7 2/3
5 1/3
1/3
1 1/3
1/2
Our teacher won't show us because she just keeps moving on to the next chapter...
2007-09-17 12:31:45 · 6 answers · asked by Anne D 1 in Food & Drink ➔ Cooking & Recipes
It's got to be an editing or printing error. It's not just values of the numbers being puzzling, but five values for the four ingredients listed in the question(?). Looks to me that the first value is the extra one inadvertently printed. The teacher probably just didn't know how to handle the situation. Books being wrong can be unsettling for a lot of people and embarrassing to the teacher, I guess.
"Reduce by 1/3" means to have 2/3 of the recipe.
2007-09-17 12:52:47 · answer #1 · answered by Observer 3 · 0⤊ 0⤋
I LOVE math. I had a great teacher in 8th grade who gave me a math book and the Teacher's Answer book. I'm 59 now and that book has really come in handy just for situations like this!! Fractions!!! For the cream cheese - 8 oz, you want 2/3rds of it so make a fraction of 8/1 (the whole number) and 2/3 and multiply them. So the top of each - the 8 and the 2 would be multiplied to make 16 and the bottom 1 and 3 multiplied would be 3. You would have 16/3rds. To make that back into a whole number it would be (dividing the top number by the bottom number) 5x3 for 15 and 1 left over to make 5 and 1/3 - that would be the answer for the cream cheese. For the butter, you would take the 1/2 times the 2/3rds. So the 1 times the 2 on the top equals 2 and the 2 times the 3 on the bottom equals 6 so your answer is 2/6ths which you would bring to it's common denominator - 1/3rd. For the vanilla it would be the fraction 2/1 (the whole number) times 2/3. So the 2 times 2 = 4 for the top and 1 times 3 = 3 on the bottom. The total is 4/3rds which equals 1 1/3. For the 3/4 times 2/3 again multiply the top numbers (3 x 2 = 6) and the bottom numbers (4 x 3 = 12) for a total of 6/12 or 1/2. That's how you do it. My son's teacher during the fractions was terrible and did the same thing your teacher did.
Hope that helps.
2007-09-17 14:01:44 · answer #2 · answered by Rli R 7 · 0⤊ 0⤋
Did you leave out an ingredient? You have 5 answers and 4 ingredients. Here is how to do the math on the rest.
Multiply 8 (the 8 ounces of cream cheese) by 1/3 to get 1/3 of 8. You should get 8/3 (the same as 2 2/3). Subtract 8/3 (or 2 2/3) from 8. The common denominator is 3 so you are basically saying 24/3 - 8/3 to get 16/3 or 5 1/3. You do the rest the same way.
2007-09-17 12:53:33 · answer #3 · answered by techneck 1 · 0⤊ 0⤋
ok, basically if you are REDUCING "MIKE L" the recipe by 1/3 you are left with 2/3 of the ingredients. You have 4 ingredients so i dont know where the first answer comes from but the rest are correct.
2/3 of 8 oz of cream cheese is 5 1/3 oz etc... Not sure where the 7 2/3 goes to tho.
>> 8/3 * 2 = 5.333333 >> 5 1/3
do the same with the other ingredients.
2007-09-17 13:02:28 · answer #4 · answered by freakyfrenchfries007 2 · 0⤊ 0⤋
what is wrong with people
1/3 of of 8oz cream cheese = 2 2/3oz so it is a trick
ther is no answer but 1/3
1/3 of 1/2 butter
1/3of 2 vanillia
1/3 of cup sugar may ???
8 TBL = cup 1/3 = 2.6 = 2 2/3
no answer
1/3
2007-09-17 13:13:50 · answer #5 · answered by Anonymous · 0⤊ 0⤋
I would say he would need 2/3 of each ingredient but that is not one of the answers. Unless I'm missing something.
2007-09-17 13:00:55 · answer #6 · answered by rob lou 6 · 0⤊ 0⤋