what is cut off ratio in thermodynamics?

Question

in a diesel cycle. it is denoted by beta B

Answer 1

# α is the cut-off ratio that is the ratio between the end and start volume for the combustion phase.
http://en.wikipedia.org/wiki/Diesel_cycle
#Tip:
One can notice that the Diesel Cycle efficiency increases with an increase in the compression ratio. One can notice that the Diesel Cycle power output increases with an increase in the compression ratio and that the Diesel Cycle power output is greater for higher cut off ratio values.

#http://members.aol.com/engware/calc3.htm

#Visit:
mech.uwa.edu.au/courses/TF209/tf_notespdf/TF209_Workbook_2005_Ch11.pdf
http://www.netl.doe.gov/publications/proceedings/04/NOx/posters/poster5loth-summary.pdf

Answer 2

Cut Off Ratio

Answer 3

This Site Might Help You.

RE:
what is cut off ratio in thermodynamics?
in a diesel cycle. it is denoted by beta B

Answer 4

The cutoff ratio is the ratio of cylinder volumes at two different points in the cycle.

See the following website.

http://www.taftan.com/thermodynamics/DIESEL.HTM

If this answer isn't sufficient, google "diesel cycle cutoff ratio"

Answer 5

Well . From what i understand. COP is T(low) / T(low) - T(hot) Everything above also can be expressed in terms of heat because all of the change in entropy terms cancled. Q(low) / Q(low) - Q(hot) The next thing to know is that for a carnot cycle (i am assuming it is) the total work done is equal to the change in heat. In other words based on the first law of thermo...the internal energy change is 0. Looking at the above equation the denominator is the change in heat. So you have the denominator now. You can now solve for Q(low). When you have Q(low) you can solve for Q(hot).