math equation dealin with parallel lines?

Question

find the equation in standard form that goes through (-3,-5) and is paralllel to 2x-5y=7

Answer 1

y = 2/5(x) - 19/5.

Consider the general equation y = mx + b, where m is the slope.
Find the slope of the equation 2x-5y = 7.
To find the slope solve for y.
You'd get y = 2/5(x) - 7/5

2/5 is your slope.

plug 2/5 into your equation when considering point (-3,-5). Parallel lines have the same slope. y = -5, and x = -3

(-5) = 2/5(-3) + b
b will equal -19/5

so your equation for the line passing through (-3,-5) is

y = 2/5(x) - 19/5

Answer 2

There are two steps and a few things you have to know first off.

-Parallel lines have equal slopes
-You should know the different formats of writing an equation of a line, those being point-slope form, slope-intercept form, and standard form.

First you would take the equation 2x-5y=7 and find the slope of that line. To do that, you need to rewrite it in slope-intercept form which is y=mx+b. Therefore, solve the equation for y in terms of x.
2x-5y=7
-5y=7-2x
y=(-7/5)+(2/5)x which can also be expressed as
y=(2/5)x-(7/5)
Remembering m is the slope in slope-intercept form, the slope of this line is 2/5.

Now you have a point and you have a slope, so if logic tells you to use point-slope form, you are right:
y-y1=m(x-x1) substitute in for x1, y1 the point given:
y-5=(2/5)(x+3)
Remember standard form is where the x and the y variables are both on the same side of the equation and the constants are on the other side:
-5=(2/5)(x+3)-y
-5=(2/5)x+(6/5)-y
-5-(6/5)=(2/5)x-y
(-31/5)=(2/5)x-y
To make this equation a whole lot neater, we can multiply through by 5:
-31=2x-5y or 2x-5y=-31

Answer 3

parallel lines won't have cross each other. and it means both line have the same slope..

first you have to find the slope for the equation you've already had:

2x-5y= 7
-5y= -2x + 7
----------------- ( : -5)
y= 2/5x + 7/5
the slope for this equation is 2/5

(-3,-5) slope 2/5

y-y1 = a (x-x1) >>>> a = slope

y- (-5) = 2/5 (x- (-3)
y+5 = 2/5x + 6/5
y= 2/5x + 6/5 - 5
y= 2/5x - 19/5
--------------------- (*5)
5y = 2x - 19
-2x + 5y = -19 or 2x-5y=19

so... 2x - 5y = 7 parallel to 2x-5y=19

Answer 4

so if it's parellel that means it has the same slope.

the slope of the given line is 2/5.

we are given values of x and y that the line passes through, so plug them in:

-5 = -3(2/5) + b

b = -19/5

so the equation is y=2/5x - 19/5

in stantard form: 2x-5y = 19


hmmm....there must be an easier way to do that, but that just shows that all problems have multuple ways to solve them.

Answer 5

strains that are parallel could have an analogous slope. if x=4 than you have a vertical line. vertical strains have undfined slope, because of the fact slope is exchange in y over exchange in x. on the standards (4,2) and (4,-2) the exchange in y is two-(-2) =4 over 4-4=0 something over 0 is undefined. x=5 could be yet another line parrallel to x=4 .could you agree that x=5 could passes for the period of the element (5,-2)

Answer 6

-5y=7-2x

y= 7/-5 - 2x/-5

y=2/5x-1.4

y=2/5x+b

-5=2/5(-3)+b

-5=-6/5+b

-19/5=b

y=2/5x-19/5