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i'm not understanding this question. i don't know how to handle a circuit with 2 voltage sources

an electric heater is connected to a constant 250V source and absorbs 1000W. Subsequently, this heater is connected to a constant 210V source. What power does it absorb from 210V source? What is the resistance of the heater? Model the electric heater as a resistor.

2007-09-13 20:21:46 · 4 answers · asked by may 1 in Science & Mathematics Engineering

4 answers

from P = (V^2)/R

you could solve for the resistance:
R=(V^2)/P
=(250^2)/1000W
= 62.5 ohms

power @ 210V source
P = (V^2)/R
=(210^2)/(62.5)
=705.6W

2007-09-13 20:34:26 · answer #1 · answered by gEL 2 · 2 0

P = VI
1000 = (250)I
I = 1000/250
I = 4A

R = V/ I
R = 250 / 4
R = 62∙5 Ω

Power @ 210V source;
P = V²/R
=(210²)/(62.5)
=705.6W

2007-09-13 23:06:39 · answer #2 · answered by Sparks 6 · 0 0

Actually, it's 2 different circuits with different supply voltages.
For the 250V circuit
P=E²/R so R=E²/P = 250²/1000 = 62.5 Ω.
Then for the 219V circuit
P=210²/62.5 = 705.6 W

Kewl?

Doug

2007-09-13 20:36:36 · answer #3 · answered by doug_donaghue 7 · 0 0

If it is a 1000 watt heater as you have described, it will draw 1000 watts regardless of the voltage supplied to it. Watts are calculated by multiplying the volts X amps. Therefore the 1000w heater at 250 volts would draw 4 amps of current, while at 210 volts, it would draw 4.76 amps. If you had large enough wire and power supply to carry the load, a 1000 watt heater at 12 volts would draw 83.33 amps.

2007-09-13 20:33:03 · answer #4 · answered by Just wonderin' 5 · 0 1

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