230=-z+148 solve for z?

Question

solve for z

230= -z+148

Answer 1

if the z is a negitive ( - ) then :

230 = -z + 148

subtract 148 from each side

82 = - z --> From this step:

Multiply each side by ( - 1) (negitive 1)

- 82 = z or z = - 82

Hope this helps!!

Answer 2

z =148 - 230

Answer 3

The answer is -82.

If -82 is substituted for the variable z, the equation becomes 230= -(-82) + 148. The two negative signs negate eachother and the 82 becomes a positive.

Answer 4

of course y and z can not the two be even via fact this makes LHS even and RHS mind-blowing. Can y, z be equivalent? if so then x*y^2 = 2y^2 + one million ----> (x - 2)*(y^2) = one million and clearly x = 3, y = one million is the only answer with integers. to any extent further i will anticipate that y is the better of y, z as reversed suggestions are rather the comparable. Can z = one million be a answer with out y = one million? xy = y^2 + 2 ----> y^2 - xy + 2 = 0 ----> y = [x + sqrt(x^2 - 8)]/2 x = 3 finally ends up in y = 2 so x = 3, y = 2, z = one million is a answer with all 3 diverse. Can z = 2? 2xy = y^2 + 5 ----> y^2 - 2xy + 5 = 0 ----> y = [2x + sqrt(4x^2 - 20)]/2 = x + sqrt(x^2 - 5) This has answer x = 3, y = 5, z = 2. For sqrt(x^2 - 5) to be an integer we prefer x^2 - 5 = ok^2 yet 2^2 and 3^2 are the only squares differing via 5 so this finally ends up in no different suggestions. I even have got here across, yet won't positioned the evidence here, that z (the smaller of y, z bear in suggestions) won't be able to be 3 or 4. This makes me suspect that there are not the different suggestions. EDIT. That final line is incorrect! i've got only got here across that x = 3, y = thirteen, z = 5 is a answer. in spite of the fact that, it is looking as though x could desire to be 3.

Answer 5

a. this is not diet and fitness.
b. this is basic algebra.. please tell me your joking
c. if not.. the answer is 82. 82+148= 230