Physics Question, please help if you can!! :)
2007-09-10 14:19:58 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Engineering
???
Did you sleep through --all-- of your high school algebra classes?
I = V/R1 + V/R2
I = V(1/R1 + 1/R2)
v = I/(1/R1 + 1/R2)
And if you can't solve it from there, you really don't have a prayer in that physics class.
Doug
2007-09-10 14:29:26 · answer #1 · answered by doug_donaghue 7 · 0⤊ 0⤋
factor V from right side, then divide both sides by the other factor
I = V/R1 + V/R2 = V(1/R1 + 1/R2)
V = I / (1/R1 + 1/R2)
now plug in the given values and evaluate
V = 3.5 / (1/24 + 1/8) = 3.5/(1/24 + 3/24) =
7/2 * 6 = 7*3 = 21 Volts
2007-09-10 23:14:15 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Do your algebra. First find a common denominator. That gives : I = (VR2+ VR1)/R1*R2. Factor out a V and multiply by the reciprocal of the R ratio. That gives V= I((R1*R2)/(R1+R2)). Plug in the numbers to get: 3.5(24*8)/(24 +8) = 21 volts.
2007-09-10 23:14:21 · answer #3 · answered by james w 5 · 0⤊ 0⤋
It's 21.
3.5 = (V/24 + V/8)
multiply both sides by 192 (24 x 8) to get rid of fractions
672 = 8V + 24V
672 = 32V
V = 21
There's probably an easier way, but this works.
2007-09-10 21:48:48 · answer #4 · answered by Melanie 1 · 0⤊ 0⤋
.11
2007-09-10 21:25:02 · answer #5 · answered by Anonymous · 0⤊ 0⤋
3.5= v/(8+24)
3.5=v/32
112=v
i believe this is right, but i could be wrong
2007-09-10 21:35:07 · answer #6 · answered by cloakedgod 1 · 0⤊ 0⤋