English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

A custom built pool measures 10.0 ft long by 50.0 ft wide. The pool has a constant depth of 12 ft.The contractor filled the pool with 37,500 kg of water. You stand 5 ft 9 in, is the water over your head?
(density of water = 1.0g/cm3 1ft = 12 in 2.54cm = 1 inch )
Show work to support your answer

2007-09-09 09:07:51 · 2 answers · asked by Vinny L 3 in Science & Mathematics Engineering

2 answers

I'm not going to do your homework for you, but I'll help you set up the solution.

Convert 37,500 kg of water to cubic feet.

37,500,000 grams = 37,500,000 cm³ of water

(1 inch / 2.54 cm)³ x (1 ft³ / 12 in)³ = ___ ft³ / cm³

37,500,000 cm³ x ___ ft³ / cm³ = ____ ft³

Divide the volume of water by the "footprint" of the pool.

Depth = _____ ft³ of water ÷ (10 ft x 50 ft) = ____ ft

Compare this value to your height of 5' 9".

2007-09-09 09:56:50 · answer #1 · answered by Thomas C 6 · 0 0

No ...the human body floats in most cases

2007-09-09 17:31:52 · answer #2 · answered by Anonymous · 0 0

fedest.com, questions and answers