Use the Composite Rule to differentiate the function g(x) = e^cosx?

6 ⤊

2007-09-08 23:23:57 · 3 answers · asked by Niall R 1 in Science & Mathematics ➔ Mathematics

y = e^(cos x)
Let u = cos x
du/dx = - sin x
y = e^u
dy/du = e^u
dy/dx = (dy / du) (du / dx)
dy/dx = (e^u) (- sin x)
dy/dx = - e ^(cos x) (sin x)

2007-09-12 22:07:24 · answer #1 · answered by Como 7 · 3⤊ 0⤋

u=cos x
g(u)=e^u
dg/du=e^u
du/dx=-sin x
so dg/dx = dg/du . du/dx = - sin x e^cos x

2007-09-09 06:30:52 · answer #2 · answered by adamcreen 2 · 3⤊ 2⤋

=-sin(x)e^(cos(x))

2007-09-14 13:46:06 · answer #3 · answered by tarek n 1 · 0⤊ 1⤋