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xy < 0

does anyone know which quadrant it would lie in? and can u show work or proof to support it?

2007-09-08 21:39:39 · 4 answers · asked by Alexis's Love Potion #9 4 in Science & Mathematics Mathematics

4 answers

That will be true when x and y have opposite signs. And that is in the second and fourth quadrants.

2007-09-08 21:45:02 · answer #1 · answered by Northstar 7 · 0 0

I am not so sure what your question is, but in your case there are two valid quadrants, for which xy<0; They are either when x<0 OR y<0, but NOT both x,y<0 - right? because negative x negative = positive.
If we talk the regular standards, then this is true in the second and forth quadrants.

2007-09-08 21:50:53 · answer #2 · answered by Anonymous · 0 0

If xy<0

For xy < 0 must have either but not both x<0 or y<0 (i.e. x and y must have different signs)

So either x<0 and y>0 (bottom right or second quadrant)
Or x>0 and y<0 (top left or fourth quadrant)

2007-09-08 21:46:46 · answer #3 · answered by piscesgirl 3 · 0 0

second and fourth excluding the axis.

2007-09-08 21:45:29 · answer #4 · answered by gjmb1960 7 · 0 0

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