chemistry problem?

Question

How many mL of a 0.524 M solution of CH3OH will contain 11.3 g of CH3OH?

Not sure how you figure this...

Answer 1

first, know the molecular weight of methanol which i think is around 32 g/mole.

convert into moles:

11.3 g x mole/32 g= 0.353 mole

0.353 mole x (liter /0.524 mole) = 0.674 L

0.674 L x (1000 mL/ L) = 674 mL

the answer would be somewhat near this figure..just check the periodic table for the correct molecular weight with the needed significant figures. :)

Answer 2

In ANY of these type problems, you MUST convert the grams to moles. To do that, compute the mole weight of methanol, which is 32.
Divide 11.3 by 32 (get about .35 moles)
The relation you use is V*M = moles.
You know that moles is 0.35 and M=0.524 mole/L. So you can solve for V, which will be in LITERS, so multiply by 1000 to get mL.