B=y-1/7x
2007-09-08 16:31:05
·
answer #1
·
answered by steinwayboy 2
·
0⤊
0⤋
(1) : Y=1/7x+b
(2) : Y=mx+b
You need to eliminate x in this system
mY = mx/7 + mb (multiply by m)
-Y/7 = -mx/7 - b/7 ( multiply by -1/7)
Then add,
mY - Y/7 = mb - b/7
mY - Y/7 = b(m - 1/7)
b = Y(m - 1/7)/(m - 1/7)
Y = b if m is not equal to 1/7
2007-09-08 16:44:15
·
answer #2
·
answered by Christine P 5
·
0⤊
0⤋
give x a value..so just say x=1 and then mx would be 1/7 then subtract mx from Y...then you have b
2007-09-08 16:32:49
·
answer #3
·
answered by s h 1
·
0⤊
0⤋
You simply can't. IF you had the coordinates of one point of this line you would need to replace the values of x and y and then you can find B.
For instance, if ( 2; 1) was a point of this line you ould need to do the following.
1 = 1/7 * 2 + b
1 = 2/7 + b
b= 1 -2/7
b= 5/7
But without a point, it is impossible.
2007-09-08 16:32:11
·
answer #4
·
answered by G88 3
·
0⤊
0⤋
In the first one,
b = Y - (1/7)x
In the 2'nd one
b = Y - mx
Doug
2007-09-08 16:33:20
·
answer #5
·
answered by doug_donaghue 7
·
0⤊
0⤋
b = y - 1/x
and you are done unless more info is given like a point (x,y) with actual values.
2007-09-08 16:33:28
·
answer #6
·
answered by 037 G 6
·
0⤊
0⤋