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Aunt Minnie drops a penyy into a wishing well n it falls for 3 seconds before hitting the water. how fast is it going when it hits?

what is the pennys average speed during its 3-second drop?

how far down is the water surface?

u dont have to tell me the answer. but will u please tell me how to do it? thanks!!

2007-09-08 15:51:08 · 7 answers · asked by Anonymous in Science & Mathematics Physics

7 answers

The force of gravity on the Earth creates an acceleration of 32 ft/s² (more precisely 32.17 /s²), or about 10 m/s². Any object in free-fall experience this gravitational acceleration as it falls towards the Earth's surface.

Acceleration (a) is defined as the change in velocity (v) over time (t): a= v/t

Solving for velocity via algebra, v=a*t

To determine the distance traveled during the time under uniform acceleration, d= 1/2 a*t^2

Check the source link for lots of details.

2007-09-08 16:02:40 · answer #1 · answered by Anonymous · 0 0

Remember, the constant for falling on this earth is 9.8 meters per sec/ per sec. That means the penny (excluding air resistence) falls 9.8 meters in the first second. It goes faster in the second second and covers 9.8 meters +9.8 meters or 19.6 meters. In the third second, it gains another 9.8 meters and falls 29.4 meters. It gains 9.8 meters every second it falls. To find the average, add up each seconds distance and divide by three. The water is the total distance away from Aunt Minnie. I hope that helps.

2007-09-08 23:04:31 · answer #2 · answered by David M 3 · 0 0

The velocity at any given instant (v) of a falling body is given by the equation:

v = gt

where v = velocity, g = acceleration due to gravity, and t = time.

On Earth, g = 9.8 m/s²

Therefore, at 3 seconds, the coin is falling at

v = 9.8 m/s² × 3s = 29.4 m/s

The average velocity of a falling body at time t is

v(average) = 1/2gt

v(average) = 1/2 (9.8 m/s² × 3 s)

v(average) = 1/2 (27.4 m/s) = 13.7 m/s

2007-09-08 23:13:15 · answer #3 · answered by Anonymous · 0 0

vf = g * t

where t is time in seconds, and g is gravitational acceleration,( 9m/s/s on earth)

plug them in. the velocity is your first answer

take 1,2,3 for t and add and divide to get the mean speed

t*s=d, so use the answer to #2 multiplied by 3 seconds to get distance.

2007-09-08 22:56:59 · answer #4 · answered by Anonymous · 0 0

v=at where v is velocity (in feet/sec), a is 32 feet/s² and t is time in seconds.

s = (1/2)at² where s is distance in feet, a is 32 ft/s² and t is time in seconds.

Average velocity is distance travelled divided by the travel time.

Have fun ☺

Doug

2007-09-08 22:59:56 · answer #5 · answered by doug_donaghue 7 · 0 0

It will depend on whether it's under free fall, distance and or gravity.

2007-09-08 22:54:31 · answer #6 · answered by Darkskinnyboy 6 · 0 0

uhhhh cat?

2007-09-08 22:53:59 · answer #7 · answered by Anonymous · 0 0

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