solve this equation??

Question

can someone please help me solve this??
i know it's not an extremely difficult problem, but it's on a quiz and we only get one try to answer it so i'd like to compare my answer with what someone else gets.

(4/x+3) - (1/x-3) = 4x/x^2-9

i know that those don't equal eachother...thats the question, im given what i typed there and have to solve it. im not saying that that is my answer!

Answer 1

(4/x+3)-(1/x-3)=4x/x^2-9
4/(x+3) -1/(x-3) =4x/(x+3)(x-3)
Multiplying both sides by (x+3)(x-3),we get
4(x+3)(x-3)/(x+3) -1(x+3)(x-3)/(x-3)=
4x(x+3)(x-3)/(x+3)(x-3)
4(x-3)-1(x+3)=4x
4x-12-x-3=4x
4x-x-4x=12+3
-x=15
x= -15

Answer 2

First of all, lets do the substraction, We need a common denominator

[4*(x-3) - (x + 3)] / (x + 3) * (x - 3) = 4x / x^2 - 9

4x - 12 - x - 3 / x^2 - 9 = 4x / x^2 - 9

(4x - 12 - x - 3 / x^2 - 9) - (4x / x^2 - 9)

As the denominator is the same, we only do the operation

- 15 - x / x^2 - 9 = 0

The only solution to this equation would be -15.

This is he only solution since if we said that 3 or -3 were solutions, there qould be a division by 0 and that is indetermined.

Answer 3

Not Even Close. You Get A z Your So Bad. The Answer Is 4+8=2=9-4*

Answer 4

I am assuming that your parentheses are in the wrong place

4/(x+3) - 1/(x-3) = 4x / (x^2-9)

factor x^2 - 9 = (x+3)(x-3)

so the common denominator is (x+3)(x-3)

Multiply the eq by (x+3)(x-3)

4(x-3) - (x+3) = 4x
4x - 12 - x - 3 = 4x
3x - 15 = 4x
x = -15