How do you differentiate y=2/(x-5)^4?

4 ⤊

i need help please!

how do you do it step by step

2007-09-08 14:34:42 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

y = 2(x - 5)^(-4)
dy/dx = -4(2)(x - 5)^(-5)(1) = -8(x - 5)^(-5) = -8/(x-5)^5

2007-09-08 14:39:46 · answer #1 · answered by Runa 7 · 1⤊ 0⤋

Let u = x-5

y = 2/u^4

dy/dx = dy/du*du/dx

= -8/u^5 * 1 = -8/(x-5)^5

2007-09-08 21:40:22 · answer #2 · answered by nyphdinmd 7 · 1⤊ 0⤋

suppose x-5=u then y=2/u^4
y=2u^(-4)
y'=2*(-4)*u'*u^(-5)
y'=-8u'u^(-5) (u=x-5,u'=1)
y'=-8/(x-5)^5

2007-09-08 21:48:03 · answer #3 · answered by Ali 2 · 1⤊ 0⤋

y=2/(x-5)^4
y=2(x-5)^-4
y'=2(-4)(x-5)^-5
y'=-8/(x-5)^5

2007-09-08 22:22:34 · answer #4 · answered by ptolemy862000 4 · 1⤊ 0⤋