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I have no idea how to figure this out-I've started it but keep getting confused. Please show me steps. Thank you so much!

2007-09-08 12:41:44 · 5 answers · asked by luckynluv001 1 in Science & Mathematics Mathematics

5 answers

n = sqrt(x) + 3
n is a number that is represented here by the function sqrt(x) + 3

if x = 9: n = sqrt(9) + 3 = 6
if n = 5,000,000 then
5,000,000 = sqrt(x) + 3
5,000,000 - 3 = sqrt(x)
4,999,997² = x
x ~= 2.49997 * 10^13

2007-09-08 12:51:39 · answer #1 · answered by z32486 3 · 0 0

N = sqrt(x) +3
when x = 9
N = sqrt(9) + 3
= 3 + 3 = 6

when x = 5 million ( 5*10^6)
N = sqrt(5*10^6) + 3
= 10^3 sqrt(5) + 3
= 2236.07 + 3
= 2239.07

2007-09-08 19:52:47 · answer #2 · answered by mohanrao d 7 · 0 0

a: N=sqrt(x)+3
=sqrt(9)+3
since a square root can be positive or negative (since both 3^2 and (-3)^2 equal nine)
N=±3+3
N=0 or 6

b: N=5000000
5000000=sqrt(x)+3
5000000-3=sqrt(x)
sqrt(x)=4999997
x=4999997^2
=2.499997*10^13

2007-09-08 19:50:40 · answer #3 · answered by Anonymous · 0 0

a: substitute in nine for the x.
N=Sqrt(9)+3=3+3=6

b: substitue in the 5,000,000 for the n
5,000,000=sqrt(x)+3
4,999,997=sqrt(x)
4,999,997²=x
which is very large.

2007-09-08 19:49:23 · answer #4 · answered by Patty C 3 · 0 0

N = +/- 3 +3 = 6 or 0

N= +/-1000sqrt(5) + 3
N = 1000sqrt(5) + 3 or N = -1000sqrt(5) +3

2007-09-08 19:49:00 · answer #5 · answered by ironduke8159 7 · 0 0

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