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If an image is 1024x768 pixels with 3 bytes/pixel and uncompressed. How long does it take to transmit it over a 56kbps modem? How do you calculate this problem? I am not looking for the answer, just the equation. Thanks.

2007-09-08 12:41:28 · 3 answers · asked by sawilamp 1 in Computers & Internet Other - Computers

3 answers

Multiply out your pixels, multiply that number by 3 to get the number of bytes. Multiply that number by 8 to get the number of bits,
because 56kbs is 56 kilobits/second.

Even then your number will be optimistic. Dial up modems add start and stop bits, which can reduce your bandwidth another 25%

2007-09-08 12:48:02 · answer #1 · answered by Computer Guy 7 · 0 0

if an image is 1024x768 pixels using the formula for area

A=length times width

1024*768= 786 432

so you now know the image is made up of 786 432 pixels

786 432 pixels * 3 bytes = 2 359 296 bytes

You now know the image is 2 359 296 bytes.

you convert bytes to kilobytes

(1 bytes = 0.0009765625 kilobytes)

2 359 296 bytes = 2 304 kilobytes

at 56 kbps that means...

2 304/56 = 41.1428571 seconds

therefore it will take 41.1428571 seconds to transmit the image

2007-09-08 19:56:27 · answer #2 · answered by Redchaos 4 · 0 0

(((1024*768)*3)/1000)/56 = seconds to transfer
Answer is 42.13 sec.

2007-09-08 19:50:18 · answer #3 · answered by Chuck R 1 · 0 1

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