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I have a few out of a hundred if anyone is willing to help me out and also explain the steps? Thank you in advance!

1) In what quadrant does the point (-2,5) lie?

2)Simplify: 3 times square root of 63

square root of 10 times (square root of 2 plus 2)

3)Find the hypotenuse when two legs of a right triangle are 6cm and 3 cm.

4) Solve for y: y-4 =3
x+3 4

5) factor: x squared-5x+6

6) let y= x squared +2x-3

7) Solve for x by taking the square root of both sides: (x-2) squared = 9

I know it's a lot and thank you again!

2007-09-08 12:20:40 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

1. quad 2
2. 3√63 = 3√(9•7) = 3•3√7 = 9√7
the rest of that blurs into ambiguity
3. h² = 6² + 3² = 36+9 = 45, h = √45 = 3√5
4. y - 4 = 3x + 34, y = 3x + 38
5. x² - 5x + 6 = (x-2)(x-3)
6. y = x² + 2x - 3. where's the question?
7. (x-2)² = 9, x-2 = ±3, x = 2+3 = 5 or x = 2-3 = -1

2007-09-08 12:58:11 · answer #1 · answered by Philo 7 · 0 0

3. a^2 + b^2 = c^2
1. 6^2 + 3^2 = c^2
2. 36 + 9 = 45
3. Take the square root of 45 to find c.

2007-09-08 19:31:23 · answer #2 · answered by shih rips 6 · 0 0

Incorrect......#1 is quadrant 2

2007-09-08 19:31:08 · answer #3 · answered by PaNaSoNiCeDgE 1 · 0 0

#1 is the 3rd quadrant

2007-09-08 19:28:14 · answer #4 · answered by devilgirl 2 · 0 0

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