I can't figure that out. Please help me, thanks!!
2007-09-08 10:34:24 · 8 answers · asked by gamer31924 2 in Science & Mathematics ➔ Mathematics
y - 1 = (-2) (x - 3)
y - 1 = - 2x + 6
y = - 2x + 7
2007-09-09 22:52:40 · answer #1 · answered by Como 7 · 2⤊ 0⤋
I think the most useful form of straight-line equations is the "slope-intercept" form
y = mx + b
The slope is given m = -2
So we can write y = -2x + b
The line passes through (3,1)
that means x = 3 and y = 1
So, let's plug in
1 = -6 + b ==> b = 7
So your equation is y = -2x + 7
2007-09-08 17:46:04 · answer #2 · answered by Christine P 5 · 1⤊ 1⤋
y=mx+c since slope = -2 therefore m = -2
y= -2x +c sub (3,1)
1 = -2(3) + c
1 = -6 +c
c= 7
y= -2x +7
2007-09-08 17:40:14 · answer #3 · answered by ジャンリン 5 · 0⤊ 1⤋
y=-2x+b
x=3 y=1
1=-2(3)+b
b=7
y=-2x+7
2007-09-08 17:42:10 · answer #4 · answered by cidyah 7 · 0⤊ 1⤋
y = -2x +b
1= -2(3) + b
7 = b
y = -2x +7
2007-09-08 17:41:59 · answer #5 · answered by ironduke8159 7 · 1⤊ 1⤋
y-1=-2(x-3)
y=-2x+6+1
y=-2x+7
2007-09-08 17:42:12 · answer #6 · answered by Ron A 2 · 0⤊ 1⤋
y=-2x+7 is the answer
2007-09-08 17:42:45 · answer #7 · answered by alex f 2 · 0⤊ 1⤋
(y - y1) = m(x - x1)
(y - 1) = -2*(x - 3)
y - 1 = -2x + 6
2x + y = 7
2007-09-08 17:45:14 · answer #8 · answered by PMP 5 · 0⤊ 1⤋