Gently heating ammonium nitrate, NH4NO3, in a test tube produces a mixture of two gases A and B. No residue remains in the tube.
The mass spectrum of gas A contains peaks at m/e (mass number) values of 16, 17 and 18, whereas that of gas B has peaks at m/e values of 14, 16, 28, 30 and 44.
Identify the peaks in the mass spectra, and suggest the molecular formulae of gases A and B.
2007-09-08 08:54:08 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
The two molecular ion peaks (M+) are 18 and 44. Given that the only atoms present are H, N and O, the peak at 18 must be due to H2O+, whilst 17 and 16 correspond to the loss of one and two H atoms respectively from M+. The peak at 44 must be due to N2O+; 30 corresponds to the loss of one N, 28 to the loss of one O, 16 to the loss of N2 and 14 to the loss of NO from the molecular ion. So A is H2O and B is N2O.
2007-09-08 09:16:47 · answer #1 · answered by Chemmunicator 5 · 1⤊ 0⤋
O+, OH+ and H2O+ for 16, 17 and 18. A = H2O.
N+, O+, N2+, NO+ and N2O+ for 14, 16, 28, 30 and 44. B = N2O.
2007-09-08 09:15:04 · answer #2 · answered by Gervald F 7 · 0⤊ 0⤋
It will decompose into gases including oxygen. But in case of detonation, it can be explosive.Large amount of the material ,due to their supporting oxidation,can cause fire and detonate.
2016-05-19 21:35:56 · answer #3 · answered by Anonymous · 0⤊ 0⤋