What is the derivative of tan((pi * x)/2)?

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2007-09-08 08:37:43 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

It's (pi/2)[1 + tan²((pi *x/2)]
or pi / [2cos²((pi * x)/2)]

2007-09-08 08:49:53 · answer #1 · answered by Nestor 5 · 0⤊ 0⤋

Derivative of tan((pi * x)/2 w.r.t. x

= sec^2 [(pi*x)/2] * d/dx [(pi*x)/2]

= (pi/2)*sec^2 [(pi*x)/2]

2007-09-08 15:43:27 · answer #2 · answered by Madhukar 7 · 1⤊ 0⤋

y=tan(pi x/2)
dy/dt=sec^2(t)pi/2
=(pi/2)*sec^2(t)

2007-09-08 15:50:36 · answer #3 · answered by Anonymous · 0⤊ 0⤋

sec^2((pi * x)/2) * pi/2

2007-09-08 15:43:03 · answer #4 · answered by steppy333 2 · 0⤊ 0⤋

pi / (2 * (cos(pi*x/2)^2)

2007-09-08 15:42:25 · answer #5 · answered by PMP 5 · 0⤊ 0⤋