11th grade algebra help..? please?

Question

i have to simplify this expression.... 10(x-3)+2(5-3x)

i dont want an answer i just want sombody to explain to me how to do this! thanks!

Answer 1

Okay.

Step One: Get rid of the brackets on the left , so multiply by 10.
10 (x - 3) + 2 (5 - 3x)
10x - 30 + 2 (5 - 3x)

Step Two: Get rid of the bracket on the right, so multiply by 2.
10x - 30 + 10 - 6x

Step Three: Put them all together
10x - 6x - 30 +10
4x - 20

I know I gave you the answer. Hopefully you understand better, and can do any other similar question.

The one above my answer is wrong. When he used the 2, it's meant to be -6, not -2.

Answer 2

10(x-3) = 10x -30 (you multiply each term in the parenthesis by 10. It is the distributivity law)
2(5-3x) = 10 -6x (similarly, you multiply each term in the parenthesis by 2. It is also the distributivity law)

finally, you sum the two terms : 10(x-3)+2(5-3x) = 10x -30 + 10 -6x = 10x -6x -30 +10 = 4x -20

Answer 3

10(x-3)+2(5-3x)
Multiply the 10 by everything inside the first set of brackets and multiply 2 by everything inside the second set of brackets.
And you get:
10x-30+10-6x

Group like terms
10x+(-6x)=4x
-30+10=-20
4x-20

Answer 4

Take the numbers next to the parentheses, and multiply them with the stuff inside the parenthesis. Like if you start with a(b-c) then the result is ab-ac. So you do that everywhere and you're going to end up with some integers and some number of X's.

For example:

start with 4(a-4)+4(8-4a)
eliminate parenthesis: 4a-16+32-16a
simplify: 16-12a

Answer 5

distribute.

10x - 30 + 10 - 6x

add like terms.
10x - 6x = 4x
-30 + 10 = -20


4x - 20

Answer 6

ok lolz its been a long time..but ill try lolz


10(x-3)+2(5-3x)

so you distribute the 10

10x-30+2(5-3x)

next you distribute the 2

10x-30+10-6x

and now add like terms

4x-20



EDIT: lolz....i fixed it ..i think its right now hehe