2007-09-08 08:01:18 · 6 answers · asked by Tom K 1 in Science & Mathematics ➔ Mathematics
= [ 81x^6 / y^4 ]^(1/2)
= 9 x ³ / y ²
2007-09-11 21:29:00 · answer #1 · answered by Como 7 · 1⤊ 0⤋
sqrt(81x^6 y^-4)
= sqrt(9x^3 y^-2)^2
= 9x^3 y^-2 =9x^3/y^2
2007-09-08 08:07:28 · answer #2 · answered by mohanrao d 7 · 0⤊ 0⤋
9x *Y(square root of 6) - 2
2007-09-08 08:12:46 · answer #3 · answered by klue 2 · 0⤊ 1⤋
9|x^3|/y^2
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You have to use the absolute sign. Otherwise the answer is not right if x<0.
2007-09-08 08:07:55 · answer #4 · answered by sahsjing 7 · 1⤊ 0⤋
sqrt(81x^6y^-4)
sqrt(81)*sqrt(x^6)*sqrt(y^-4)
+/-9*(x^6)^(1/2)*(y^-4)^(1/2)
+/-9*x^3*y^-2
(+/-9x^3)/y^2
2007-09-08 08:07:59 · answer #5 · answered by Matiego 3 · 0⤊ 0⤋
sr is 9x^3y^-2
2007-09-08 08:04:13 · answer #6 · answered by Anonymous · 0⤊ 0⤋