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8 answers

Let :-
AC = 5 (hypotenuse)
AB = 4
BC = 3
B is right angle.

sin C = 4 / 5
C = 53.1°

sin A = 3 / 5
A = 36.9°

2007-09-12 06:35:06 · answer #1 · answered by Como 7 · 1 0

This is a right angle triangle because 3^2+4^2=5^2 (Pythagoras theorem)
the angle which is oppoisite to the 5-length-side will be equal to 90 degrees.
Using the laws of sign we can find the other angles:
suppose that A is the angle which is opposite to 4-length-side and B is the angle which is opposite to the 3-length-side.
sin A/4=sin(90)/5=1/5
and it'll be the same for the last angle.

2007-09-08 08:38:13 · answer #2 · answered by medo 1 · 0 0

in this particular case
3^2 + 4^2 = 9 + 16 = 25 = 5^2
sum of the squres of the two legs = square of third leg
so it is a right angled triangle.
you can find out the other angles by trignometric relation
Let ABC is a triangle with angle B =90 degrees
AC = 5
AB = 4
BC = 3
sin A = opposite side to angle A/ hypotenuse
=BC/AC = 3/5
A = sin-(3/5)
A = 37 degrees
C = 180-(90 + 37) (since sum of the angles in a triangle is 180 degrees)
= 180 - 127 = 53 degrees

2007-09-08 08:03:02 · answer #3 · answered by mohanrao d 7 · 0 0

if it's 3,4,5 then 3^2+4^2 = 5^2 so you know that the angle opposite the long side is 90 degrees (pi/2) . Find arcsin 3/5 then subtract that from 90 for the remaining angle.

2007-09-08 07:52:17 · answer #4 · answered by Anonymous · 0 0

Well, 3²+4²=5², so you already know this is a right triangle, and the angle opposite the longest side is 90°. The angle opposite the side of length three has a sine of 3/5 (remembering that sine=opposite/hypotenuse), so that angle is arcsin (3/5), which is about 36.87°. Similarly, the remaining angle is arcsin (4/5), for the same reason, and is about 53.13°.

2007-09-08 07:50:15 · answer #5 · answered by Pascal 7 · 2 0

Just use the formula Cos A = (b^2+c^2-a^2)/2bc
where a, b and c are the opposite sides of the angles A,B and C of the triangle.
Similarly use it for Cos B and Cos C . Thus u will get the angles.

2007-09-08 07:51:43 · answer #6 · answered by Bibo 1 · 0 1

Use the "regulation of Sines" from trigonometry: [A / sin(a)] = [B / sin(b)] = [C / sin(c)] the place a, b and c are the angles, A is the realm length opposite perspective a, B is the realm opposite b, C is the realm opposite c. So letting A = the dimensions you already know, use the regulation of Sines to discover B. Then use it to discover C. sturdy success.

2016-12-16 14:53:12 · answer #7 · answered by Anonymous · 0 0

You have triangle legs? No freakin way...you must be from another country .... how kool is that?

2007-09-08 07:53:05 · answer #8 · answered by http://fuelthearmy.com 3 · 0 1

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