A BODY COVERS HALF THE DISTANCE WITH A SPEED OF 20m/s AND THE OTHER HALF WITH A SPEED OF 30m/s .WHAT IS THE AVERAGE VELOCITY OF THE BODY DURING THE WHOLE JOURNEY.
2007-09-08 06:46:29 · 6 answers · asked by umashankar 1 in Science & Mathematics ➔ Geography
It is NOT 25m/s, but 24m/s.
Let me explain.
Suppose the distance is 120m.
Then at 30m/s, it takes 2 secs to cover the first 60m
At 20m/s, it takes 3 secs to cover the other 60m
So total time is 5 secs to cover 120 m
So the average speed is 24m/s
2007-09-08 09:47:03 · answer #1 · answered by Anonymous · 0⤊ 0⤋
You just do the typical average-arithmetic. It went at 30 and then at 20, each for the same distance. You add the two numbers and divide by two. So 30+20 = 50 and divided by 2 = 25 m/s.
2007-09-08 06:52:54 · answer #2 · answered by Rich Z 7 · 0⤊ 0⤋
permit's assume you holiday for one million minute. this suggests you will holiday 1800 m because one million/2 of the gap replaced into coated at 30 m/s. So, in 30 s we've traveled 900 m at 30 m/s. It then takes us how long to holiday the final 900 m at 40 m/s? d = V*t t = d/V = 900 / 40 = 22.5 s So we now understand our holiday circumstances, multiply to get the common: (30 m/s * 30 s + 40 m/s * 22.5s) / fifty two.5 s = accepted velocity OR d/t = V = 1800m/fifty two.5s = 34.29 m/s
2016-12-31 16:54:58 · answer #3 · answered by ? 3 · 0⤊ 0⤋
20m/s + 30m/s = 50
50/2 =
25m/s
2007-09-08 06:50:42 · answer #4 · answered by Nick H 2 · 0⤊ 0⤋
Is your caps lock key stuck? If not, turn it off.
2007-09-08 06:52:03 · answer #5 · answered by Anonymous · 0⤊ 0⤋
50/2
25m/s very quick
2007-09-08 06:52:56 · answer #6 · answered by Anonymous · 0⤊ 0⤋