A 1.25-kg object is moving in the x direction at 17.4 m/s. Just 3.41 s later, it is moving at 26.8 m/s at 34° to the x axis. What are the magnitude and direction of the force applied during this time?
2007-09-08 03:54:21 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Physics
Find the acceleration "a" from the equation
v₁= v₀ + a t
where "v₁" is the final velocity, "v₀" is the initial velocity and "t" is time.
Then find the force from equation
F = m a
Where "m" is the mass.
Remember that velocity, acceleration and force are vectors.
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2007-09-08 05:27:09 · answer #1 · answered by oregfiu 7 · 1⤊ 0⤋
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2016-10-18 07:57:39 · answer #2 · answered by jeremie 4 · 0⤊ 0⤋
You've been given information to calculate the x and y components of the velocity at 2 different times. You can then calculate the x and y components of the acceleration, and hence the force.
2007-09-08 04:31:04 · answer #3 · answered by Anonymous · 0⤊ 0⤋