the sum of 3 consectutive integers is -30. Find the greatest integer.?

Answer 1

Greatest integer is -9.

All three: (-11) + (-10) + (-9) = -30

Hope this helps!

Answer 2

Since the three numbers are consecutive in a series, their differences must be one (1) from one number to another.

Let x = be the first no.
Let x +1 = the second no.
Let x +2 = the third no.

The equation satisfying your condition (that their total is -30)
will be:

x + (x+1) + (x +2) = -30

Removing the parentheses:

x+x+1+x+2 = -30
3x+3 = -30
3x = -30-3
3x= -33
x = - 11 The first nO.

The other two nos. are:

x +1 = -11+1 = -10 The second no.

x + 2 = -11+2 = -9 The third no. AND GREATEST
(THE ANSWER TO YOUR QUESTION)

Proof of your condition being satisfied by our answers:

(-11) + (-10) + (-9) = -30
-11-10- 9= -30
-30= -30

Answer 3

Since they are consecutive, and (-1,0,1) is clearly not a solution, we can say all the integers are negative, and, as such, all must be more than -30.

Let our three numbers be x,y,z.

Then we know x + y + z = -30.

Also, from this, we can say that the average of the numbers must be 10, since

(x+y+z)/ 3 = -10.

There is only one way three consecutive numbers can average another, and that is if the middle number is that average.

so I suggest our numbers are -9, -10, -11. Lets check

-9 + -10 + -11 = -30.

The greatest of these integers is -9.

Answer 4

let those three consecutive integers be x,(x+1),(x+3)

now, x+x+1+x+3= -30

==> 3x+3= -30

==> 3x= -33

==> x= -11.

therefore 2nd integrer= -10

3 rd integer= -9

-9> -10> -11

therefore the greatest integer is -9.

Answer 5

Let us take the smallest integer as y
Then, the second integer= y+1
And 3rd integer=y+2
Sum=30

y+y+1+y+2=-30
y+y+y+1+2= -30
3y+3= -30
3y= -30-3
3y=-33
y= -33/3= -11

y= -11
1st integer= y= -11
2nd integer=y+1 = -11+1= -10
3rd integer = y+2= -11+2= -9

Three integers= -9,-10,-11
Greatest integer= -9

Answer 6

Let x = largest, x - 1 = in-between, x - 2 = smallest

Equation:
x + x - 1 + x - 2 = - 30
3x - 3 = - 30
3x = - 27
x = - 9

In-between: - 9 - 1 or -10

Smallest: - 9 - 2 or - 11

Answer: - 9 is the largest

Proof:
= - 9 - 10 - 11
= - 30

Answer 7

let the three consecutive integers be n-1,n &n+1
their sum=3n=30
n=10,
so the greatest integer is 11. ANS.

Answer 8

n+(n+1)+(n+2) = -30

3n + 3 = -30

3n = -33

n = -11

Thus, -11, -10, and -9 are the integers

Answer 9

x + x+1 + x+2 = - 30
3x + 3 = - 30
3x = - 33
x = - 11
x + 1 = - 10
x + 2 = - 9

greatest is - 9

Answer 10

-9