2007-09-08 03:17:30 · 11 answers · asked by Deepak B 1 in Science & Mathematics ➔ Mathematics
(a+b)^2=(a+b)*(a+b)=
=a^2+ab+ab+b^2=
a^2+2ab+b^2
...
2007-09-08 03:22:26 · answer #1 · answered by Anonymous · 0⤊ 0⤋
(a + b) (a + b)
= a ² + a b + b a + b ²
= a ² + a b + a b + b ²
= a ² + 2 a b + b ²
2007-09-09 22:38:56 · answer #2 · answered by Como 7 · 0⤊ 0⤋
dude let us assume the value of a=2,b=3.
now, (a+b)^2=(2+3)^2
= 5^2
=25.
now lets check a^2+b^2+2ab
2^2+3^2+2*3*2
=4+9+12
=25.
therefore from the two answers
(a+b)^2=a^2+b^2+2ab.
2007-09-08 03:24:15 · answer #3 · answered by nawaz_xan6 2 · 0⤊ 0⤋
(a+b)^2. Expand out the brackets using FOIL.
(a+b)^2 = a^2 + ab + ba + b^2.
= a^2 + 2ab + b^2
= a^2 + b^2 = 2ab as required.
2007-09-08 03:22:29 · answer #4 · answered by steppy333 2 · 0⤊ 0⤋
I think you mean squared when you're typing this, just so you know, (a+b)^2 is squared. To figure this out you just have to expand (a+b)^2:
(a+b)^2 *expand the exponent
= (a+b) x (a+b) *multiply everything in one bracket by everything in the other
= (axa) + (axb) + (axb) + (bxb) *simplify the brackets
= a^2 + ab + ab + b^2 *now collect like-terms
= a^2 + 2ab + b^2
You could also use the Pascal's Triangle method, go look it up if you want, but it's kind of annoying to work with.
2007-09-08 03:27:29 · answer #5 · answered by Anonymous · 0⤊ 0⤋
(a+b)^2=(a+b)(a+b)
=a(a+b)+b(a+b)
a^2+ab+ab+b^2
=a^2+b^2+2ab. ANS.
2007-09-08 03:41:50 · answer #6 · answered by Anonymous · 1⤊ 0⤋
i think you mean (a+b)^2 = a^2 + 2ab + b^2
but here's how...
(a+b)^2 = (a+b)*(a+b)
multiply that out and you get
a*a + a*b + b*a + b*b
simplify a little and you get
a^2 + ab + ab + b^2
simplify some more and you get
a^2 + 2ab + b^2
see? :)
2007-09-08 03:25:26 · answer #7 · answered by Andy 1 · 0⤊ 0⤋
(a+b)2 means that it's a+b plus another a+b so that's (a+b)x(a+b) so it's a x a+b and b x a+b so that's axa plus axb plus bxa plus bxa (axa+axb+bxa+bxb) or a^2 + ab +ab + b^2 or a^2 + 2ab + b^2 then switch the 2nd with the 3rd.
2007-09-08 03:41:45 · answer #8 · answered by Josh Kortos duh! 2 · 0⤊ 0⤋
Simple. 1) Take a square with side 'a' (say 8cm). 2)Take another square with side b, say 6 cm 3) Take 2 rectangles, each with length 'a' i.e. 8cm and breadth 'b' i.e. 6cm. 4)Take a fourth square with side a+b i.e. 14 cm. Now paste the first two squares and the two rectangles on the last square. You will see that they overlap it completely. This proves the identity.
2016-04-03 10:48:33 · answer #9 · answered by Anonymous · 0⤊ 0⤋
a^2 +ab+ab+b^2
then
a^2+2ab+b^2....
You can also use binomial theorem
2007-09-08 03:26:43 · answer #10 · answered by wisten 2 · 0⤊ 0⤋