what is the voltage at high inpedence state in digital circuits?

Question

suppose take an example of tristate buffer then wat will be the voltage in its high impledence in a voltmeter or measurable device.

Answer 1

May be it helps if you get some knowledge on the use of tri-state buffers. Those buffers can be paralleled with other tri-state buffers at the output.
When the buffer is enabled, then it will drive the outputs either hi or low according to the inputs. Then the buffer under question is disabled (no CE / chip enable) then all the outputs of this buffer are at hi-impedance and another buffer that is connected in parallel can do its work in driving the outputs of the whole circuit populated with several tri-state buffers with shared outputs.

So your question is not of any practical use. Because the hi-z state does, by "letting go" the output lines, just allow the other buffer to do the work.

Answer 2

An output in tristate us
O/C it's an OPEN CIRCUIT

with a digital voltmeter connected to gound it will read zero
with a digital volmeter connecter to +5V it will read zero

To find tristated outputs
connect two 10K resistors in series between 0v and 5v
and connect the oscilloscope or voltmeter probe to the midpoint and the digital output (lo side to 0v)

Tristated outputs and faulty outputs will read 2.5 volts

(adjust values if the average of logic highs and lows are not midway)

Answer 3

The higher the Resistance the less the B plus, Current doesn't know the difference between digital and analog!! reverse the polarity on something digital or analog and see what hap pends'

Answer 4

If there is no driving source, it will be whatever all of the leakage currents of the (disabled) outputs and the inputs that are tied together force it to be. There's really no good way to tell.

Doug

Answer 5

usually, Hi-Z, is like an open circuit,
you use a pull-up resistor on a hi-z output.
so if the pullup is to 5 volts, it become 5volts.
no pullup resistor, it just floats around.