How do I convert from Nm to lb. ft of torque?

Question

If an engine is rated at 260 Nm @ 1,600 RPM, how many Pound Feet of Torque is that?

Thank you!

Answer 1

191.7 lbs-ft

You can try some exotic conversion factor thing or you can use a web site listed below. The web site listed below is quick and accurate.

Answer 2

Nm To Ft Lbs

Answer 3

This Site Might Help You.

RE:
How do I convert from Nm to lb. ft of torque?
If an engine is rated at 260 Nm @ 1,600 RPM, how many Pound Feet of Torque is that?

Thank you!

Answer 4

hope these formulas and examples help.

Useful Equations



Force (Newtons)

F = m x a m = mass (kg)

a = acceleration (m/s2)



Motor Torque (Newton-meters)

T = F x d F = force (Newtons)

d = moment arm (meters)





Power (Watts)

P = I x V I = current (amps)

V = voltage (volts)



P = T x ω T = torque (Newton-meters)

ω = angular velocity (radian/second)





Unit Conversion

Length (1 in = 0.0254 m)



Velocity (1 RPM = 0.105 rad/sec)



Torque (1 in-lb = 0.112985 N-m)



Power (1 HP = 745.7 W)





Example 1

Determine if the following motor can be used to lift a 5-kg load using a 0.5-m lever arm.



Merkle-Korff Gearmotor specifications

Stall Torque = 40 in-lb

Stall Current = 3.5 amps



5 kg

0.5 m




Solution



Convert Stall Torque from in-lb to N-m

1 in-lb = 0.112985 N-m

40 in-lb = 40 x 0.112985 N-m = 4.5194 N-m



Calculate the Force required to lift the 5-kg load

F = m x a = 5 kg x 9.81 m/s2 = 49.05 N



Calculate the Torque required to lift the Force with the lever arm

T = F x d = 49.05 N x 0.5 m = 24.525 N-m



We cannot perform the lift with this set-up, because the stall torque is smaller than the torque required for the lift. We must either shorten the length of the lever arm, or we must choose another motor with a higher stall torque to perform this operation.





Example 2

Using the same motor as in Example 1 with a 12-V power supply:

a) Calculate the power used by the motor to rotate a 5-kg load at 50 RPM using a 3-inch lever arm.

b) Calculate the current draw from the battery to perform this operation.





Solution



Convert inches to meters

1 in = 0.0254 m

3 in = 0.0762 m



Calculate the Force required to lift the 5-kg load

F = m x a = 5 kg x 9.81 m/s2 = 49.05 N



Calculate the Torque required for this operation

T = F x d = 49.05 N x 0.0762 m = 3.738 N-m



Note- This toque is lower than the motor’s stall torque, so this operation is possible using the specified motor, mass, and lever arm



Convert RPM to radians/second

1 RPM x 2π rad/rev x 1 min/60 sec = 0.105 rad/sec

ω = 50 rev/min x 0.105 rad/sec/RPM = 5.25 rad/sec



Calculate the Power required for this operation

P = T x ω = 3.738 N-m x 5.25 rad/sec = 19.622 W



Calculate the Current draw from the battery (use the supply voltage in this calculation)

I = P/V = 19.622 W/12 V = 1.635 Amps



Note- This current is smaller than the maximum allowable current draw of the motor.

Answer 5

1.356

foot lbs x 1.56 = NM

newton meters x 0.737 = foot lbs

Answer 6

use google...

or just multiply by .737

http://www.google.com/search?hl=en&q=1+Nm+in+lb+ft

Answer 7

1 nm equals .737561 lbs........

Answer 8

Here's a formula my friend:

http://www.convert-me.com/en/bb/viewtopic.php?t=655