i've been up all night trying to understand it but i cant please someone help me :(
http://img524.imageshack.us/img524/1196/untitledea2.jpg
hope u can undestand it from that picture i drew
Find i0, i1. and i2
please help me id be grateful forever
2007-09-04 21:50:52 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Engineering
I forgot to put in one more node so look at this image
http://img527.imageshack.us/img527/627/untitledcl4.jpg
2007-09-04 21:52:22 · update #1
i0 is equal to zero. It is connected to the ground node of the other loop and it has no independent sources.
i1 and i2 depend on v1. Calculate v1 by voltage division:
v1 = 60 * 5 / (5 + 1) = 50 volts
The total current in the other loop is 6e-3 * 50 = 0.3 Amp or 300 mA.
Use a current division for magnitudes of i1 and i2:
i1 = 300 * 0.5 / (2 + 0.5) = 60 mA
i2 = 300 * 2 / (2 + 0.5) = 240 mA
Warning, note the direction of the arrows. i1 and i2 flow opposite the current source!!! Thus, the values above must be negated. So then:
i0 = 0 mA
i1 = -60 mA
i2 = -240 mA
2007-09-04 23:46:30 · answer #1 · answered by joe_ska 3 · 1⤊ 0⤋
Hope this is correct:
To maintain balance, i0 should be zero. So,
i0 = 0
V1 is [5/(5+1)]*60 = 50 V
Then we know that 6e-3V1 = 300 mA.
We also know that 300mA = -(i1+i2) and from the ratio of the resistors values that i1 and i2 go through, we know that i1=(1/4)i2. Solving those equations gives:
i1 = -60 mA
i2 = -240 mA
2007-09-05 00:06:13 · answer #2 · answered by acid_funkid 2 · 0⤊ 0⤋
not sure what youre asking what exactly are u wanting to know the circuit looks incomplete
2007-09-04 22:00:23 · answer #3 · answered by Ive gone diving 4 · 0⤊ 0⤋