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I need help trying to figure out this problem, 1000 ft of 18 gauge wire has a 6.385 resistance. How do you get A and D?

A 6 V source is connected to a 100 Ω resistor by two 12 ft lengths of 18 gauge copper wire. The total resistance is the resistance of both wires added to the 100 Ω resistor. Determine the following: (pg )

(a) Total resistance =

(b) Current = 59.9 mA

(c)Voltage drop across the 100 Ω resistor. = 5.99 V

(d)Voltage drop across each length of wire. = 4.61 mV

2007-09-01 09:17:59 · 1 answers · asked by Chris 2 in Science & Mathematics Engineering

1 answers

I don't know how you found the current without finding the total resistance.
One foot of 18 gauge wire has 6.385/100 = 0.006385 ohms
12 feet of 18 gauge wire has 0.006385 x 12 = 0.07662 ohms

a) Total resistance:
2(0.07662) + 100 = 100.15324 ohms

d) E = RI = (0.07662)(59.9) = 4.59 mV

2007-09-01 09:49:03 · answer #1 · answered by jsardi56 7 · 0 0

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