I have an old 8mm video camera that I want to use to transfer to DVD but I can't find the original ac/dc adapter for it. I have one for another camera with the same amperage (2A) but the adapter puts out 7.4 V instead of the 6V rated for the camera I want to run. How close do I have to get in voltage [assuming the polarity matches] without causing serious damage? What if I used a cheap wall-wart that puts out 6V but only a measly 300mA?
2007-08-30 12:40:06 · 3 answers · asked by ranolf 1 in Consumer Electronics ➔ Other - Electronics
The safe answer is that you have to match the voltage, but the current rating you can just try it to see if it will work. If there isn't enough current, it may just charge the battery very slowly or may not be able to operate and charge the battery at the same time.
Too high of a voltage with no internal regulation could blow any number of components, too low of a voltage may cause an over draw of current and be even worse (I did this once)
2007-08-31 09:09:58 · answer #1 · answered by TahoeT 6 · 0⤊ 0⤋
First the voltage has to be very close to 6 volts. 7.4 is too far off. Next, the current has to be 2A or more. If the current is less the camera will not work. That wall wart will not do the trick. You will need to find a power supply that is 6 volts and at least 2 amps.
2007-08-30 12:52:18 · answer #2 · answered by gkk_72 7 · 0⤊ 1⤋
I t depends on whether you camera has an internal voltage regulator that makes sure that whatever goes in ends up as 6V. Otherwise you are way over a typical tolerance for overvoltage and stand a good chance of damaging it.
If you have a potentiometer and a voltmeter you could turn up the resistance of the pot in series with the camera to make sure that the camera gets just 6 volts.
2007-08-30 12:49:57 · answer #3 · answered by Rich Z 7 · 0⤊ 1⤋