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an existing 33 kv over head line, 100 km in length, with ACSR (DOG) wire insttaled, i need to add new loads for new consumers, what is the current carying capacity and the in amps and the max load in kva i can use in this case ?

2007-08-30 07:38:42 · 2 answers · asked by ELECTRICAL-ENGINEER 1 in Science & Mathematics Engineering

2 answers

I can not find an ACSR conductor with a code name of DOG. The link below lists all the sizes and their corresponding names. The names all appear to be types of birds.

Once you find the correct wire size, the column on the far right provides the ampacity of each conductor.


***** Update *****

The second link below provides dimensions of DOG ACSR, but no ampacity. Overall diameter = 14.15 mm² which is 0.557 square inches.

Using the first link below, we find that this conductor is between two AWG ACSR sizes. We'll look up the ampacity of those two sizes and split the difference.

Name ------ Diameter ------- Ampacity
Leghorn -- 0.530 inches --- 273 amps
DOG ------ 0.557 inches --- 285 amps (estimated)
Guinea --- 0.576 inches --- 297 amps

Let's call this one 285 amps!

285 amps x 33 kV x √3 = 16,270 kVA.
(assumes this is a 3Ø line)

2007-08-30 10:52:34 · answer #1 · answered by Thomas C 6 · 1 1

the PEAK load current is180 amps (according to Diamond cables, http://www.dicabs.com/condfiles/compare.asp#p7)
33kV * 180A = 5940kVA per wire, if you have 3 wires, that would be a total. of 17820kVA (peak). However at 100km, you'll want to consider the line resistance (0.36 ohm /km or 36 ohm @ 100km) and losses. The table at the link above says losses are 3499kw at peak load, (total for 3 lines)

The "Dog" "Rabbit" "Weasel" etc. designation seem to be Asian designations, the link the previous answerer gave is to an "American Wire Group" table.

I'm a little surprised that someone making connections to a 33kV line doesn't know this, but maybe that's an example of specialization, I know how to use a search engine, but I wouldn't touch a 33kV line with a 10 foot hot stick.

2007-08-31 13:07:37 · answer #2 · answered by tinkertailorcandlestickmaker 7 · 0 0

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